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2016-05-31 12:58:06 +0100 received badge  Famous Question (source)
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2016-02-08 05:37:16 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

For anyone interested, the issue is being discussed here: https://github.com/ging/fiware-idm/issues/40 .

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2016-02-02 08:52:35 +0100 commented answer KURENTO AND ANDROID | ONE2MANY EXAMPLE

Ok, thank you. We are now trying crosswalk and also chrome custom tabs.

2016-02-02 02:47:42 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Ok, thank you very much for helping me!! I created the issue... let's see :)

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2016-01-28 08:32:54 +0100 asked a question KURENTO AND ANDROID | ONE2MANY EXAMPLE

Hello Kurento Users,

I am playing with one2many example. It is working (with some freezing issues in the stream).

But my question is: I want to display the stream in my Android App. I tried to do with a WebView but it is not working: the page is loaded but the stream is not displayed, it only shows the loading cursor.

I tired it in Chrome and Firefox and it is working. WebView is supporting WebRTC from Lollipop version.

Is there possible any workaround? I don't won't to view the stream in a separate browser but embed in the App.

Thank you.

2016-01-28 08:16:08 +0100 commented answer KEYROCK AND ANDROID APP INTEGRATION

I have too many doubts as you noticed from my question, could you please suggest me an working Android example?... may be on GitHub. Thank you.

2016-01-28 08:05:20 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Done, I edited the question by adding the logs. That logs are from horizon console, keystone is not generating any logs in the console. Thanks!

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2016-01-28 02:25:15 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

I gave it a look, but the problem is not that one, because I am able to create the application successfully.

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2016-01-27 05:52:44 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Yes, I think too that idm is the admin. The last step is skipped by all the users: idm, user0, and other new users. In fact when I click NEXT at "select icon" step, it does not go to step 3...it is skipped and Application is created. I don't understand why?...

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2016-01-27 02:58:32 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Another clue which could help solve the problem: when I register an application ther are 3 steps: application details, app icon and permission and roles. The last step is automatically skipped, I go through only first 2 steps but why?

2016-01-27 02:53:34 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Nop, user0 is not admin, in fact it is not able to see all the applications registered by other users.

2016-01-27 02:38:41 +0100 commented answer KEYROCK AND APPLICATION REGISTRATION

Thank you for the answer. I think user0 must be the admin of the system so it has the rights to remove or edit roles for the applications registered in the fiware lab instance, but what I did was as follow: - Registered a new user, activated the account, registered my application.How is it possible?

2016-01-26 09:34:05 +0100 asked a question KEYROCK AND APPLICATION REGISTRATION

Hello guys,

when I register an application it is not possible to remove it, to change roles and permissions and i can't see oAUth2 credentials, why??

I followed official guide to install idm and register an application, please help...

Here is the log I get when registering the application:

[28/Jan/2016 13:51:39] "GET /idm/myApplications/create/ HTTP/1.1" 200 13742 CacheKeyWarning: Cache key contains characters that will cause errors if used with memcached: u":1:<role application_id="d59c43b160674fe6b28378f26c8d0746," id="807bcb009bb047a7b0611531b3167cd1," is_internal="True," links="{u'self':" u'http:="" 127.0.0.1:35357="" v3="" os-roles="" roles="" 807bcb009bb047a7b0611531b3167cd1'},="" name="purchaser">" WARNING:py.warnings:CacheKeyWarning: Cache key contains characters that will cause errors if used with memcached: u":1:<role application_id="d59c43b160674fe6b28378f26c8d0746," id="807bcb009bb047a7b0611531b3167cd1," is_internal="True," links="{u'self':" u'http:="" 127.0.0.1:35357="" v3="" os-roles="" roles="" 807bcb009bb047a7b0611531b3167cd1'},="" name="purchaser">" DEBUG:idmlogger:Application Test App created [28/Jan/2016 13:52:06] "POST /idm/myApplications/create/ HTTP/1.1" 302 0 [28/Jan/2016 13:52:06] "GET /idm/myApplications/5a852ce979af422dad557688c89e5043/step/avatar/ HTTP/1.1" 200 13302 DEBUG:idmlogger:Avatar for application 5a852ce979af422dad557688c89e5043 saved [28/Jan/2016 13:52:22] "POST /idm/myApplications/5a852ce979af422dad557688c89e5043/step/avatar/ HTTP/1.1" 302 0 [28/Jan/2016 13:52:22] "GET /idm/myApplications/5a852ce979af422dad557688c89e5043/step/roles/ HTTP/1.1" 302 0 [28/Jan/2016 13:52:22] "GET /home/ HTTP/1.1" 302 0 [28/Jan/2016 13:52:22] "GET /idm/ HTTP/1.1" 200 13753 [28/Jan/2016 13:52:22] "GET /filters/organizations?page=1&userid=idm HTTP/1.1" 200 322 [28/Jan/2016 13:52:22] "GET /filters/applications?page=1&userid=idm HTTP/1.1" 200 661

Thank you.

2016-01-26 09:34:04 +0100 asked a question KEYROCK AND ANDROID APP INTEGRATION

I am trying to integrate KeyRock in my Android App which has already a local sign in/sign up system.

Now I would like to use my local KeyRock instance on my computer as remote server to authenticate the users:

My objective is to send local user sign up/sign in data to the KeyRock server to sign in and sign up users ...

I tried to do some REST calls to the server trying to authenticate idm account but I always receive 403 http error code as response.

Otherwise how can I use auth 2.0 token system provided by KeyRock by registering my "application", my application is an Android App and not a web App. I followed the KeyRock youtube course but it explains how to register a web App.

In fact when registering an Application you need to specify two URLs which Android App does not have!

Is it possible to reach my goal with KeyRock o I should search for some other alternatives?

By the way, in case we have a web App only the user who registered the web application can login through Fiware account?

Kind regards, thank you.